If you declare
int a[20], b[10];you are reserving space for 20 ints called a[0] .. a[19], and 10 ints called b[0] .. b[9]. As in many languages, you can work through an array with a for loop such as:
for (i = 0; i < 20; i++) {
do something with a[i];
}
A shortcut way to initialize arrays is this:
int b[] = {2, 4, 6, 8, 10, 9, 7, 5, 3, 1};
#include < stdio.h >
main() {
int i,min,max;
int arr[] = {2, 4, 6, 8, 10, 9, 7, 5, 3, 1};
min = max = 0;
for // insert code here
if (arr[i] > arr[max]) // and here
if (arr[i] < arr[min]) // and here
}
printf("Max %d Min %d\n", arr[max], arr[min]);
}
A string in C is just an array of char. The final entry of the array needs to be the special char '\0'.
Try the following program:
#include < stdio.h >
main() {
char c[] = {'a', 'b', 'c', '\0'};
printf("%s\n", c);
}
Now change that last character to something other than '\0'.
If you use the syntax below, the terminator will be placed there for you. Work with the following program and see if you can answer the questions below:
#include < stdio.h >
main() {
int i,min,max;
char carr[] = "To be or not to be";
min = max = 0;
i = 0;
while (carr[i] != '\0') {
if (carr[i] > carr[max]) max = i;
if (carr[i] < carr[min]) min = i;
i++;
}
printf("Max %d Min %d\n", carr[max], carr[min]);
}